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How to fix status 500 error instantiating servlet class

if you need both approaches, it should be similar to below: = " ServletExample", urlPatterns = { " / servletExample" } ) public s a ClassNotFoundException issue. ClassNotFoundException: LoginServlet". Make sure you have placed the jar file containing LoginServlet in the class- path which is normally WEB- INF/ classes and/ or WEB- INF/ lib. you can simply add tag under tag of web. xml, It will work. enter image description here. The exception states ClassNotFoundException, which means your servlet class is not found for instantiation. Make sure the servlet class ( inclusive of its package structure) is [ resent in the WEB- INF/ classes directory. EDIT: After checking the. I think somethin wrong in this section: < servlet- class> website.

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  • Video:Servlet class error

    Status error servlet

    HomeServlet< / servlet- class>. Instead try: < servlet- class> website. My current error is: HTTP Status 500 - Error instantiating servlet class com. I am adding my web. Please provide me the possible solutions. - < web- rvlet can be mapped using web. xml or annotation. You are using both of them. Remove below portion from web. xml then clean and build your project then you are good to go. < servlet> < servlet- name> Hello< / servlet- name>. The error shows that Tomcat is unable to create an instance of your WeatherServlet class. You should make its constructor and other methods public too. You can even make use of the default constructor by removing the is because each servlet in a app has a unique id.

    and tomcat causes problem with two servlets having same id. In my case missing private static final long serialVersionUID = 1L; line caused the same error. I added the line. Sometimes, when creating servlet the class file may not be generated in build folder. We should clean the project then build. It worked for me.